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Question: Answered & Verified by Expert
Two liquids of densities \(d_1\) and \(d_2\) are flowing in identical capillary tubes uder the same pressure difference. If \(t_1\) and \(t_2\) are time taken for the flow of equal quantities (mass) of liquids, then the ratio of coefficient of viscosity of liquids must be
PhysicsMechanical Properties of FluidsVITEEEVITEEE 2022
Options:
  • A \(\frac{d_1 t_1}{d_2 t_2}\)
  • B \(\frac{t_1}{t_2}\)
  • C \(\frac{\mathrm{d}_2}{\mathrm{~d}_1} \frac{\mathrm{t}_2}{\mathrm{t}_1}\)
  • D \(\sqrt{\frac{\mathrm{d}_1 \mathrm{t}_1}{\mathrm{~d}_2 \mathrm{t}_2}}\)
Solution:
2495 Upvotes Verified Answer
The correct answer is: \(\frac{d_1 t_1}{d_2 t_2}\)
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