Two masses M 1 = 5 kg and M 2 = 10 kg are connected at the ends of an inextensible string passing over a frictionless pulley as shown. When the masses are released, then the acceleration of the masses will be

Question

Two masses M 1 ​ = 5 kg and M 2 ​ = 10 kg are connected at the ends of an inextensible string passing over a frictionless pulley as shown. When the masses are released, then the acceleration of the masses will be, g, g /2, g /3, g /4

MARKS App · Accepted Answer

Since M 2 ​ > M 1 ​ , therefore M 2 ​ moves downwards and M 1 ​ moves upwards with an acceleration a as shown in the figure. $ Free body diagram of M 1 ​ im g src = " h ttp s : // c d n − q u es t i o n − p oo l . g e t ma r k s . a pp / p y q / aiim s / V P 6 M 68 nbb XZ i Z 6 d 8 o i N f l a 3 Ew 27 n qO m 85 M Y G k d V U 3 N I . or i g ina l . f u ll s i ze . p n g " > b r > T h ee q u a t i o n o f m o t i o n f or M_1 i s T − M 1 ​ g = M 1 ​ a F ree b o d y d ia g r am o f M_2 im g src = " h ttp s : // c d n − q u es t i o n − p oo l . g e t ma r k s . a pp / p y q / aiim s / xu r 4 u B 27 S − − L f F A C W g a fd A RN V M z O W D M Kze j I T 2 MZ h TM . or i g ina l . f u ll s i ze . p n g " > b r > T h ee q u a t i o n o f m o t i o n f or M_2 i s M 2 ​ g − T = M 2 ​ a A dd in g ( i ) an d ( ii ) , w e g e t a = M 2 ​ + M 1 ​ ( M 2 ​ − M 1 ​ ) g ​ = ( 10 + 5 ) ( 10 − 5 ) g ​ = 3 g ​ $

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