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Question: Answered & Verified by Expert
Two mercury drops (each of radius r) merge to form a bigger drop. The surface energy of the bigger drop, if T is the surface tension, is
PhysicsMechanical Properties of FluidsNEET
Options:
  • A 253 πr2T
  • B 4 π2T
  • C 2 πr2T
  • D 283 πr2T
Solution:
1846 Upvotes Verified Answer
The correct answer is: 283 πr2T
Let R be the radius of the bigger drop, then Volume of bigger drop =2× volume of small drop

43πR3=2×43πr3R=21/3r

Surface energy of bigger drop,

E=4πR2T=4×22/3πr2T=28/3πr2T

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