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Two metallic spheres of radii $1 \mathrm{~cm}$ and $3 \mathrm{~cm}$ are given charges of $-1 \times 10^{-2} \mathrm{C}$ and $5 \times 10^{-2} \mathrm{C}$, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is
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The correct answer is:
$3 \times 10^{-2} C$
$\quad \frac{k x}{1 \mathrm{~cm}}=\frac{k(Q-x)}{3 \mathrm{~cm}}$
$3 x=Q-x \Rightarrow 4 x=Q$
$x=\frac{Q}{4}=\frac{4 \times 10^{-2}}{4} C=1 \times 10^{-2}$
$Q^{\prime}=\mathrm{Q}-x=3 \times 10^{-2} \mathrm{C}$
$3 x=Q-x \Rightarrow 4 x=Q$
$x=\frac{Q}{4}=\frac{4 \times 10^{-2}}{4} C=1 \times 10^{-2}$
$Q^{\prime}=\mathrm{Q}-x=3 \times 10^{-2} \mathrm{C}$
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