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Question: Answered & Verified by Expert
Two neutral conducting spheres of diameters $8 \mathrm{~cm}$ and $2 \mathrm{~cm}$ separated with a distance of $15 \mathrm{~cm}$ between their centres are joined by a thin conducting wire. A charge of $100 \mathrm{nC}$ is given to one of the spheres and the system is allowed to reach electrostatic equilibrium. The electric potential at a point on the line joining the centres of the two spheres where the net electric field becomes zero is ____ V. (Neglect the charge acquired by the wire and $\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}$)
PhysicsElectrostaticsAP EAMCETAP EAMCET 2017 (25 Apr Shift 1)
Options:
  • A $10.8 \times 10^3$
  • B $10.8 \times 10^4$
  • C $5.4 \times 10^3$
  • D $5.4 \times 10^4$
Solution:
1570 Upvotes Verified Answer
The correct answer is: $10.8 \times 10^3$
No solution. Refer to answer key.

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