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Question: Answered & Verified by Expert
Two parallel plate capacitors of capacitance C and 2C are connected in parallel and charged to a potential difference V0. The battery is then disconnected and the region between the plates of the capacitor C is completely filled with a material of dielectric constant 2. The potential difference across the capacitors now becomes
PhysicsElectrostaticsNEET
Options:
  • A V04
  • B V02
  • C 3V04
  • D V0
Solution:
2487 Upvotes Verified Answer
The correct answer is: 3V04


Initial state



As both capacitors have the same capacitance total charge =C V 0 +2C V 0

=3C V 0

It will be divided equaly so q 1 = q 2 = 3C V 0 2 & potential = q C = ( 3C V 0 2 ) 2C = 3 V 0 4

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