Two particles A and B execute simple harmonic motion of period T and 5 T / 4 . They start from mean position. The phase difference between them when the particle A completes one oscillation will be

Question

Two particles A and B execute simple harmonic motion of period T and 5 T / 4 . They start from mean position. The phase difference between them when the particle A completes one oscillation will be, π / 2, Zero, 2 π / 5, π / 4

MARKS App · Accepted Answer

Equation of motion of the particles are X 1 = A 1 sin 2 π T 1 t and X 2 = A 2 sin 2 π T 2 t ∴ Phase difference Δ ϕ = 2 π T 1 − 2 π T 2 t = 2 π T − 2 π 5 T / 4 t at t = T Δ ϕ = 2 π − 4 × 2 π 5 T T = 2 π 5

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