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Two particles are executing simple harmonic motion of the same amplitude $\mathrm{A}$ and frequency $\omega$ along the $x$-axis. Their mean position is separated by distance $X_0\left(X_0>A\right)$. If the maximum separation between them is $\left(X_0+A\right)$, the phase difference between their motion is :
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The correct answer is:
$\frac{\pi}{2}$
$\frac{\pi}{2}$
$\phi_1=0$
$\phi_2=\frac{\pi}{2}$
$\phi_2=\frac{\pi}{2}$
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