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Question: Answered & Verified by Expert
Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to A and T, respectively. At time t=0 one particle has displacement A while the other one has displacement -A2 and they are moving towards each other. If they cross each other at time t, then t is:
PhysicsOscillationsJEE MainJEE Main 2016 (09 Apr Online)
Options:
  • A 5T6
  • B T3
  • C T4
  • D T6
Solution:
1372 Upvotes Verified Answer
The correct answer is: T6


Angle covered to meet =60o=π3rad

Therefore,  t= θ ω = π 3 × T 2π = T 6

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