Two particles of masses 2 kg and 3 kg are projected horizontally in opposite directions from the top of a tower of height 39 . 2 m with velocities 5 m s - 1 and 10 m s - 1 respectively. The horizontal range of the centre of mass of two particles is [ g = 9 . 8 m s - 2 ]

Question

Two particles of masses 2 kg and 3 kg are projected horizontally in opposite directions from the top of a tower of height 39 . 2 m with velocities 5 m s - 1 and 10 m s - 1 respectively. The horizontal range of the centre of mass of two particles is [ g = 9 . 8 m s - 2 ], 8 2 m in the direction of 2 kg, 8 2 m in the direction of 3 kg, 8 m in the direction of 2 kg, 8 m in the direction of 3 kg

MARKS App · Accepted Answer

Range of C.M = V c m 2 h g V c m = m 1 v 1 + m 2 v 2 m 1 + m 2 V c o m = − 2 × 5 + 3 × 10 2 + 3 = 4 m / s Range = 4 2 × 39.2 9.8 = 8 2

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