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Two point charges $+8 q$ and $-2 q$ are located at $x=0$ and $x=L$ respectively. The location of a point on the $x$ axis at which the net electric field due to these two point charges is zero is
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The correct answer is:
$2 \mathrm{~L}$
$2 \mathrm{~L}$
$-\frac{\mathrm{k} 2 q}{(\mathrm{x}-\mathrm{L})^2}+\frac{\mathrm{k} 8 \mathrm{q}}{\mathrm{x}^2}=0$
$\Rightarrow \mathrm{x}=2 \mathrm{~L}$
$\Rightarrow \mathrm{x}=2 \mathrm{~L}$
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