Two point charges of $ 1 \mu \mathrm{C} $ and $ -1 \mu \mathrm{C} $ are separated by a distance of $ 100 Å $. A point $ P $ is at a distance of $ 10 \mathrm{~cm} $ from the mid-point and on the perpendicular bisector of the line joining the two charges. The electric field at $ P $ will be

Question

Two point charges of $ 1 \mu \mathrm{C} $ and $ -1 \mu \mathrm{C} $ are separated by a distance of $ 100 Å $. A point $ P $ is at a distance of $ 10 \mathrm{~cm} $ from the mid-point and on the perpendicular bisector of the line joining the two charges. The electric field at $ P $ will be, $ 9 \mathrm{~N} \mathrm{C}^{-1} $, $ 0.9 \mathrm{~V} \mathrm{~m}^{-1} $, $ 90 \mathrm{~V} \mathrm{~m}^{-1} $, $ 0.09 \mathrm{~N} \mathrm{C}^{-1} $

MARKS App · Accepted Answer

The point lies on the equatorial line of a short dipole. ∴ E = p 4 π ε 0 r 3 = 9 × 10 9 10 - 6 × 10 - 8 10 - 1 3 = 9 × 10 - 2 = 0.09 N C - 1 .

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