Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 k g m s - 1 is given to the 5 k g mass at an angle of 60 ° to the line joining the masses. The velocity of the 10 k g mass just after the impulse will be

Question

Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 k g m s - 1 is given to the 5 k g mass at an angle of 60 ° to the line joining the masses. The velocity of the 10 k g mass just after the impulse will be, 2 3 m s - 1, 1 3 m s - 1, 2 m s - 1, zero

MARKS App · Accepted Answer

Apply impulse equation, along string Impulse = Δ p 10 × 1 2 = 10 + 5 v v = 1 3 m s - 1

Search any question & find its solution

Looking for more such questions to practice?