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Two polaroids have their polarizing directions parallel so that the intensity of a transmitted light is maximum. The angle through which either polaroid must be turned if the intensity is to drop by one-half is
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The correct answer is:
$135^{\circ}$
$135^{\circ}$
For $I=\frac{I_0}{2}$ and $I=I_0 \cos ^2 \theta=\frac{I_0}{2}$ $\therefore \theta=45^{\circ}$
Therefore the angle through which either polaroids turned is $135^{\circ}\left(=180^{\circ}-45^{\circ}\right)$
Therefore the angle through which either polaroids turned is $135^{\circ}\left(=180^{\circ}-45^{\circ}\right)$
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