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Two poles are separated by a distance of $3.14 \mathrm{~m}$. The resolving power of human eye is $1 \mathrm{~min}$ of an arc. The maximum distance from which he can identify the two poles distinctly is
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$10.8 \mathrm{~km}$
Given, distance between poles $(d)=3.14 \mathrm{~m}$
Resoolving power $=1$ min or $1^{\prime}$
Let maximum distance of two poles from eye to be resolved distinctly be $x$. Then, angle on eye in minute for two poles can be found using figure given below
$\theta=\frac{d}{x} \times \frac{180}{\pi} \times 60$
$\Rightarrow \quad 1=\frac{3.14}{x} \times \frac{180}{\pi} \times 60$
$\Rightarrow \quad x=\frac{3.14 \times 180 \times 60}{\pi}=10794.5$
$=10.8 \mathrm{~km}$
Resoolving power $=1$ min or $1^{\prime}$
Let maximum distance of two poles from eye to be resolved distinctly be $x$. Then, angle on eye in minute for two poles can be found using figure given below
$\theta=\frac{d}{x} \times \frac{180}{\pi} \times 60$
$\Rightarrow \quad 1=\frac{3.14}{x} \times \frac{180}{\pi} \times 60$
$\Rightarrow \quad x=\frac{3.14 \times 180 \times 60}{\pi}=10794.5$
$=10.8 \mathrm{~km}$
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