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Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$
and frequency $200 \mathrm{~Hz}$. The distance between two consecutive antinodes is
Options:
and frequency $200 \mathrm{~Hz}$. The distance between two consecutive antinodes is
Solution:
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Verified Answer
The correct answer is:
$0 \cdot 125 \mathrm{~m}$
AS,
$\begin{aligned}
f &=\frac{v}{\lambda} \quad[v=50 \mathrm{~m} / \mathrm{s}] \\
\therefore \lambda &=\frac{50}{200}=1 / 4
\end{aligned}$
Now, Distance blw two antinode $=1 / 2$
$\begin{array}{r}=1 / 8=0.125 \mathrm{~m} \\ \text { < option-2 }\end{array}$
$\begin{aligned}
f &=\frac{v}{\lambda} \quad[v=50 \mathrm{~m} / \mathrm{s}] \\
\therefore \lambda &=\frac{50}{200}=1 / 4
\end{aligned}$
Now, Distance blw two antinode $=1 / 2$
$\begin{array}{r}=1 / 8=0.125 \mathrm{~m} \\ \text { < option-2 }\end{array}$
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