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Two projectiles $\mathrm{A}$ and $\mathrm{B}$ are thrown with the same speed but angles are $40^{\circ}$ and $50^{\circ}$ with the horizontal. Then
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The correct answer is:
A will fall earlier
$\mathrm{T}=\frac{2 \mathrm{u} \sin \theta}{\mathrm{g}},$ lesser is the value of $\theta$, lesser is $\sin \theta$ and hence lesser will be the time taken. Hence A will fall earlier.
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