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Two rings of same mass 'M' and radius 'R' are so placed that their centre is
common and their planes are perpendicular to each other. The moment of inertia
of the system about an axis passing through the centre and perpendicular to any
one ring is
Options:
common and their planes are perpendicular to each other. The moment of inertia
of the system about an axis passing through the centre and perpendicular to any
one ring is
Solution:
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Verified Answer
The correct answer is:
$\frac{3 \mathrm{MR}^{2}}{2}$
$\mathrm{MR}^{2}+\frac{\mathrm{MR}^{2}}{2}=\frac{3 \mathrm{MR}^{2}}{2}$
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