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Question: Answered & Verified by Expert
Two rings of the same radius (r) and mass (m) are placed such that their centres are at a common point and their planes are perpendicular to each other. The moment of inertia of the system about an axis passing through the centre and perpendicular to the plane of one of the ring is
PhysicsRotational MotionNEET
Options:
  • A 12mr2
  • B mr2
  • C 32mr2
  • D 2 mr 2
Solution:
2929 Upvotes Verified Answer
The correct answer is: 32mr2
I1 = mr2
I2 = moment of inertia about one of the diameters



        =12mr2
I=I1+I2=32mr2

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