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Two satellites 'A' and 'B' of same mass are revolving round the earth at height '2R'
and '3R' respectively above the surface of the earth. The ratio of kinetic energies
of A to B will be
Options:
and '3R' respectively above the surface of the earth. The ratio of kinetic energies
of A to B will be
Solution:
2433 Upvotes
Verified Answer
The correct answer is:
$4: 3$
(B)
$\begin{aligned}
\text { K.E. } &=\frac{1}{2} \frac{\mathrm{GMm}}{\mathrm{r}} \\
\therefore \frac{\mathrm{K}_{1}}{\mathrm{~K}_{2}} &=\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}} \\
&=\frac{3 \mathrm{R}+\mathrm{R}}{3 \mathrm{R}+\mathrm{R}}=\frac{4}{3}
\end{aligned}$
$\begin{aligned}
\text { K.E. } &=\frac{1}{2} \frac{\mathrm{GMm}}{\mathrm{r}} \\
\therefore \frac{\mathrm{K}_{1}}{\mathrm{~K}_{2}} &=\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}} \\
&=\frac{3 \mathrm{R}+\mathrm{R}}{3 \mathrm{R}+\mathrm{R}}=\frac{4}{3}
\end{aligned}$
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