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Two Simple Harmonic Motions of angular frequency 100 and $1000 \mathrm{rad} \mathrm{s}^{-1}$ have the same displacement amplitude. The ratio of their maximum accelerations is
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Verified Answer
The correct answer is:
$1: 10^2$
$$
\frac{\left(a_{\max }\right)_1}{\left(a_{\max }\right)_2}=\frac{\omega_1^2 A}{\omega_2^2 A}=\left(\frac{100}{1000}\right)^2=\frac{1}{10^2}
$$
\frac{\left(a_{\max }\right)_1}{\left(a_{\max }\right)_2}=\frac{\omega_1^2 A}{\omega_2^2 A}=\left(\frac{100}{1000}\right)^2=\frac{1}{10^2}
$$
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