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Question: Answered & Verified by Expert
Two spherical soap bubbles of radii a and b in vacuum coalesce under isothermal conditions. The resulting bubble has a radius given by
PhysicsMechanical Properties of FluidsJEE Main
Options:
  • A a+b2
  • B aba+b
  • C a2+b2
  • D a+b
Solution:
1988 Upvotes Verified Answer
The correct answer is: a2+b2
Since, the bubbles coalesce in vacuum and there is no change in temperature, hence its surface energy does not change. This means that the surface area remains unchanged. Hence,

4 π a2+4 π b2=4π R2 or R=a2+b2

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