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Two straight lines passing through the point $\mathrm{A}(3,2)$ cut the line $2 \mathrm{y}=\mathrm{x}+3$ and $\mathrm{x}$ -axis perpendicularly at $\mathrm{P}$ and $\mathrm{Q}$ respectively. The equation of the line PQ is
Options:
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Verified Answer
The correct answer is:
$7 x+y-21=0$
$\because$ Coordinates of $Q$ are $(3,0) \&$ it passes through $P Q$.
$\therefore$ Putting the values of $(x=3) \&(y=0)$ in options we get:
Equation of line $\mathrm{PQ}=7 \mathrm{x}+\mathrm{y}-21=0$
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