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Question: Answered & Verified by Expert
Two thin lenses of focal lengths $f_1$ and $f_2$ are in contact and coaxial. The combination is equivalent to a single lens of power
PhysicsRay OpticsJEE Main
Options:
  • A $f_1+f_2$
  • B $\frac{f_1 f_2}{f_1+f_2}$
  • C $\frac{1}{2}\left(f_1+f_2\right)$
  • D $\frac{f_1+f_2}{f_1 f_2}$
Solution:
2588 Upvotes Verified Answer
The correct answer is: $\frac{f_1+f_2}{f_1 f_2}$
$P=\frac{1}{F}=\frac{f_1+f_2}{f_1 f_2}$

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