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Question: Answered & Verified by Expert
Two thin rings each of radius R are placed at a distance  d apart. The charges on the rings are +q and q. The potential difference between their centres will be -

PhysicsElectrostaticsJEE Main
Options:
  • A qR4πε0d2
  • B q2πε01R-1R2+d2
  • C zero
  • D q4πε01R-1R2+d2
Solution:
1148 Upvotes Verified Answer
The correct answer is: q2πε01R-1R2+d2
VA=kqR-kqR2+d2

VB=-kqR-+  +k2R2+d2-

VA-VB=2kqR-2kqR2+d2

VA-VB=q2πε01R-1R2+d2

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