Two vectors P → and Q → have equal magnitudes. If the magnitude of P → + Q → is n times the magnitude of P → - Q → , then angle between P → and Q → is

Question

Two vectors P → and Q → have equal magnitudes. If the magnitude of P → + Q → is n times the magnitude of P → - Q → , then angle between P → and Q → is, sin - 1 n - 1 n + 1, cos - 1 n - 1 n + 1, sin - 1 n 2 - 1 n 2 + 1, cos - 1 n 2 - 1 n 2 + 1

MARKS App · Accepted Answer

| P → | = | Q → | = x … i | P → + Q → | = n | P → - Q → | P 2 + Q 2 + 2 P Q cos θ = n 2 P 2 + Q 2 - 2 P Q cos θ Using ( i ) in above equation, cos θ = n 2 - 1 1 + n 2 θ = cos - 1 n 2 - 1 n 2 + 1

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