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Two waves $y=0.25 \sin 316 t$ and $y=0.25 \sin 310 t$ are travelling in same direction. The number of beats produced per second will be
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$3 / \pi$
$n_1=\frac{316}{2 \pi}$ and $n_2=\frac{310}{2 \pi}$ Number of beats heard per second $=n_1-n_2=\frac{316}{2 \pi}-\frac{310}{2 \pi}=\frac{3}{\pi}$
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