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Two wires $A$ and $B$ are stretched by the same load. The radius of wire $A$ is double the radius of wire $\mathrm{B}$. The stress on the wire $\mathrm{B}$ as compared to the stress on the wire
A is
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A is
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The correct answer is:
four times
(B)
stress $=\frac{\text { Force }}{\text { Area }}$
$\therefore$ stress $\propto \frac{1}{\pi r^{2}}$
Thus, $\frac{S_{B}}{S_{A}}=\left[\frac{r_{A}}{r_{B}}\right]^{2}=(2)^{2} \Rightarrow S_{B}=4 S_{A}$
stress $=\frac{\text { Force }}{\text { Area }}$
$\therefore$ stress $\propto \frac{1}{\pi r^{2}}$
Thus, $\frac{S_{B}}{S_{A}}=\left[\frac{r_{A}}{r_{B}}\right]^{2}=(2)^{2} \Rightarrow S_{B}=4 S_{A}$
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