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Question: Answered & Verified by Expert
Typical silt (hard mud) particle of radius 20 μm is on the top of lake water, its density is 2000 kg m-3 and the viscosity of lake water is 1.0 mPa, density is 1000 kg m-3. If the lake is still(has no internal fluid motion). The terminal speed with which the particle hits the bottom of the lake is .......... ms-1
PhysicsMechanical Properties of FluidsNEET
Options:
  • A 0.67
  • B 0.77
  • C 0.87
  • D 0.97
Solution:
2711 Upvotes Verified Answer
The correct answer is: 0.87
v=29r2(ρ-σ)gɳ

= 2 9 × ( 20× 10 6 ) 2 ( 20001000 )×9.8 1.0× 10 3

=8.7×10-4 m s-1=0.87 mm s-1

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