Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Uranium-238 decays to Thorium-234 with half-life 5×109 yr . The resulting nucleus is in the excited state and hence further emits γ -rays to come to the ground state. It emits 20 γ -rays per second. The emission rate will drop to γ-rays per second in
PhysicsNuclear PhysicsNEET
Options:
  • A 1.25×109 yr
  • B 1010 yr
  • C 10-8 yr
  • D 1.25×10-9 s
Solution:
2282 Upvotes Verified Answer
The correct answer is: 1010 yr
Number of emitted γ-rays per second is proportional to no of uranium particles left undecayed

fraction of particles undecayed, N N 0 = ( 1 2 ) n

Where n is the number of half-lives

5 20 = ( 1 2 ) n

n=2

Total time =2×5× 10 9 years

= 10 10 yr

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.