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Question: Answered & Verified by Expert
Under standard conditions, the density of a gas is 1.3mg cm-3 and the velocity of propagation of sound, in it, is 330 m s-1. The number of degrees of freedom of gas is
PhysicsKinetic Theory of GasesJEE Main
Solution:
2317 Upvotes Verified Answer
The correct answer is: 5

Vsound=γPρ and γ=1+2f

1+2f=vsound2×ρP

1+2f=(330)2×(1.3)1.01×105

1+2f=1.40

f=5

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