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Question: Answered & Verified by Expert

Under the action of a force a 2 kg body moves such that its position x in meters as a function of time t is given by x=t44+3 . Then work done by the force in first two seconds is

PhysicsWork Power EnergyNEET
Options:
  • A 6 J
  • B 10 J
  • C 7 J
  • D 64 J
Solution:
2385 Upvotes Verified Answer
The correct answer is: 64 J
x=t44+3

dxdt=4t34+0

v=t3

Using work energy theorem

w=k=12mv22-12mv02

=122232-03 

=64 J

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