Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Under the same load, wire A having length 5.0 m and cross section 2.5×10-5 m2 stretches uniformly by the same amount as another wire B of length 6.0 m and a cross section of 3.0×10-5 m2 stretches. The ratio of the Young's modulus of wire A to that of wire B will be:
PhysicsMechanical Properties of SolidsJEE MainJEE Main 2023 (31 Jan Shift 2)
Options:
  • A 1:4
  • B 1:1
  • C 1:10
  • D 1:2 
Solution:
2182 Upvotes Verified Answer
The correct answer is: 1:1

Elongation in uniform wire under load is given by, Δl=FlSY, where S is area of cross-section.

As F is same for both wire and Δl is also same, we can write

ΔlF=lSYlASAYA=lBSBYB

52.5×10-5×YA=63×10-5×YB

YAYB=1

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.