Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Units of \( a \) in Van der Waal's equation of state is
PhysicsUnits and DimensionsJEE Main
Options:
  • A \( \mathrm{N} \mathrm{m}^{4} \mathrm{~mol}^{-1} \)
  • B \( \mathrm{N} \mathrm{m}^{2} \mathrm{~mol}^{-1} \)
  • C \( \mathrm{N}^{2} \mathrm{~m} \mathrm{~mol}^{-1} \)
  • D \( \mathrm{N} \mathrm{m}^{4} \mathrm{~mol}^{-2} \)
Solution:
2086 Upvotes Verified Answer
The correct answer is: \( \mathrm{N} \mathrm{m}^{4} \mathrm{~mol}^{-2} \)

Van der Waals equation is given as P+an2V2Vnb=nRT, here P is pressure, V is volume, T is temperature, n is the number of moles, and R is the universal gas constant.

The dimensional formula of pressure isP=ForceArea=MLT2L2=ML-1T2 

The dimensional formula of the volume is L3

As we know, the quantities with the same dimensions are added or subtracted. Thus, the dimension of P=the dimension of an2V2.

Therefore, a=PV2n2=ML-1T-2L32mol2=ML5T-2mol-2

Thus, the unit of constant a is N m4 mol-2.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.