Search any question & find its solution
Question:
Answered & Verified by Expert
Upon mixing equal volumes of aqueous solutions of $0.1 \mathrm{M} \mathrm{HCl}$ and $0.2 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$, the concentration of $\mathrm{H}^{+}$in the resulting solution is $-$
Options:
Solution:
1694 Upvotes
Verified Answer
The correct answer is:
$0.25 \mathrm{~mol} / \mathrm{L}$
$0.1 \mathrm{MHCl}, \mathrm{V}$ volume
$\mathrm{H}^{+}$moles $=0.1 \mathrm{~V}$
$0.2 \mathrm{MH}_{2} \mathrm{SO}_{4}, \mathrm{~V}$ volume
$\mathrm{H}^{+}$moles $=0.2 \times 2 \times \mathrm{V}=0.4 \mathrm{~V}$
Total moles of $\mathrm{H}^{+}=0.4 \mathrm{~V}+0.1 \mathrm{~V}=0.5 \mathrm{~V}$
$\left[\mathrm{H}^{+}\right]=\frac{\text { Moles }}{\text { Vol. }}=\frac{0.5 \mathrm{~V}}{2 \mathrm{~V}}=0.25 \mathrm{M} / \mathrm{I}$
$\mathrm{H}^{+}$moles $=0.1 \mathrm{~V}$
$0.2 \mathrm{MH}_{2} \mathrm{SO}_{4}, \mathrm{~V}$ volume
$\mathrm{H}^{+}$moles $=0.2 \times 2 \times \mathrm{V}=0.4 \mathrm{~V}$
Total moles of $\mathrm{H}^{+}=0.4 \mathrm{~V}+0.1 \mathrm{~V}=0.5 \mathrm{~V}$
$\left[\mathrm{H}^{+}\right]=\frac{\text { Moles }}{\text { Vol. }}=\frac{0.5 \mathrm{~V}}{2 \mathrm{~V}}=0.25 \mathrm{M} / \mathrm{I}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.