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Question: Answered & Verified by Expert
Urea on slow heating gives
ChemistryCarboxylic Acid DerivativesJEE Main
Options:
  • A $\mathrm{NH}_2 \mathrm{CON} \cdot \mathrm{HNO}_2$
  • B $\mathrm{NH}_2 \mathrm{CONHCONH}_2$
  • C $\mathrm{HCNO}$
  • D $\mathrm{NH}_2 \mathrm{CONH}_2 \cdot \mathrm{HNO}_3$
Solution:
2414 Upvotes Verified Answer
The correct answer is: $\mathrm{NH}_2 \mathrm{CONHCONH}_2$
$2 \mathrm{NH}_2 \mathrm{CONH}_2 \rightarrow \mathrm{NH}_2 \mathrm{CONHCONH}_2+\mathrm{NH}_3$

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