Search any question & find its solution
Question:
Answered & Verified by Expert
Using an AC voltmeter the potential difference in the electrical line in a house is read to be $234 \mathrm{~V}$. If line frequency is known to be 50 cycles/s, the equation for the line voltage is
Options:
Solution:
1891 Upvotes
Verified Answer
The correct answer is:
$\quad V=331 \sin (100 \pi t)$
$E=E_{0} \sin \omega t$
Voltmeter read rms value $\therefore E_{0}=\sqrt{2} \times 234 \mathrm{~V}=331 \mathrm{~V}$
and $\omega t=2 \pi n t=2 \pi \times 50 \times t=100 \pi t$ Thus, the equation of the line voltage $E=331 \sin (100 \pi t)$
Voltmeter read rms value $\therefore E_{0}=\sqrt{2} \times 234 \mathrm{~V}=331 \mathrm{~V}$
and $\omega t=2 \pi n t=2 \pi \times 50 \times t=100 \pi t$ Thus, the equation of the line voltage $E=331 \sin (100 \pi t)$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.