Search any question & find its solution
Question:
Answered & Verified by Expert
Using the standard electrode potential, find out the pair between which redox reaction is not feasible.
$E^{\ominus}$ values $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}=+0.77 ; \mathrm{I}_2 / \mathrm{I}^{-}=+054$
$\mathrm{Cu}^{2+} / \mathrm{Cu}=+0.34 ; \mathrm{Ag}^{+} / \mathrm{Ag}=0.80 \mathrm{~V}$
Options:
$E^{\ominus}$ values $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}=+0.77 ; \mathrm{I}_2 / \mathrm{I}^{-}=+054$
$\mathrm{Cu}^{2+} / \mathrm{Cu}=+0.34 ; \mathrm{Ag}^{+} / \mathrm{Ag}=0.80 \mathrm{~V}$
Solution:
2451 Upvotes
Verified Answer
The correct answer is:
Ag and $\mathrm{Fe}^{3+}$
Ag and $\mathrm{Fe}^{3+}$
(a)
This reaction is feasible, since $E_{\text {cell }}^{\circ}$ is positive.
(b)
This reaction is feasible, since $E_{\text {cell }}^{\circ}$ is positive.
(c)
This reaction is feasible, since $E_{\text {cell }}^{\circ}$ is positive.
(d)
This reaction is not feasible, since $E_{\text {cell }}^{\circ}$ is negative.
This reaction is feasible, since $E_{\text {cell }}^{\circ}$ is positive.
(b)
This reaction is feasible, since $E_{\text {cell }}^{\circ}$ is positive.
(c)
This reaction is feasible, since $E_{\text {cell }}^{\circ}$ is positive.
(d)
This reaction is not feasible, since $E_{\text {cell }}^{\circ}$ is negative.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.