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Variation of resistance of the conductor with temperature is as shown
The temperature co-efficient \( (\alpha) \) of the conductor is
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The temperature co-efficient \( (\alpha) \) of the conductor is
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The correct answer is:
\( \frac{m}{R_{0}} \)
According to equation of straight line, we have
\[
y=m x+c
\]
Temperature coefficient \( (\alpha) \) of the conductor is
\[
\alpha=\frac{\text { slope }}{y-\text { intercept }}=\frac{m}{R_{0}}
\]
\[
y=m x+c
\]
Temperature coefficient \( (\alpha) \) of the conductor is
\[
\alpha=\frac{\text { slope }}{y-\text { intercept }}=\frac{m}{R_{0}}
\]
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