Volume of 0.1 M H 2 S O 4 required to neutralize 30 m L of 0.2 N N a O H is

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Question: Answered & Verified by Expert

Volume of

0.1 M

H_{2} S O_{4}

required to neutralize

30 m L

of

0.2 N

N a O H

is

ChemistryRedox ReactionsNEET

Options:

A $30 mL$
B $15 mL$
C $40 mL$
D $60 mL$

Solution:

1450 Upvotes Verified Answer

The correct answer is:

30 mL

0.1 M o f H_{2} S O_{4} \Rightarrow 0.2 N o f H_{2} S O_{4}

∴

N_{1} V_{1} = N_{2} V_{2}

[N_{1} = 0.2 N H_{2} {SO}_{4}]

0.2 \times V_{1} = 30 \times 0.2

∴

V_{1} = 30 m L

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