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Water is flowing through a horizontal pipe in stream line flow. At the narrowest part of the pipe
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velocity is maximum and pressure is minimum
Using equation of continuity,
$\mathrm{A}_1 \mathrm{~V}_1=\mathrm{A}_2 \mathrm{~V}_2$
In streamlined flow, as the product of $\mathrm{Av}$ is a constant, the velocity at the narrowest part will be maximum.
By using Bernoulli's principle,
$\mathrm{P}+\frac{1}{2} \rho v^2+\rho g h=\text { Constant }$
We see that $\rho g h$ is constant because the pipe is horizontal.
As velocity increases, for the equation to remain constant, $\mathrm{P}$ has to decrease.
$\therefore \quad$ Velocity will be maximum and pressure is minimum
$\mathrm{A}_1 \mathrm{~V}_1=\mathrm{A}_2 \mathrm{~V}_2$
In streamlined flow, as the product of $\mathrm{Av}$ is a constant, the velocity at the narrowest part will be maximum.
By using Bernoulli's principle,
$\mathrm{P}+\frac{1}{2} \rho v^2+\rho g h=\text { Constant }$
We see that $\rho g h$ is constant because the pipe is horizontal.
As velocity increases, for the equation to remain constant, $\mathrm{P}$ has to decrease.
$\therefore \quad$ Velocity will be maximum and pressure is minimum
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