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Water rises in a capillary tube to a certain height such that the upward force due to surface tension is balanced by $75 \times 10^{-4} \mathrm{~N}$ force due to the weight of the liquid. If the surface tension of water is $6 \times 10^{-2} \mathrm{Nm}^{-1}$, the inner circumference of the capillary must be
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$12.5 \times 10^{-2} \mathrm{~m}$
$6 \times 10^{-2} \times$ Circumference $=$ Force
$\therefore$ Circumference $=\frac{75 \times 10^{-4}}{6 \times 10^{-2}}=12.5 \times 10^{-2} \mathrm{~m}$
$\therefore$ Circumference $=\frac{75 \times 10^{-4}}{6 \times 10^{-2}}=12.5 \times 10^{-2} \mathrm{~m}$
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