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Water rises upto a height ' $\mathrm{h}$ ' in a capillary tube on the surface of the earth. The
value of 'h' increases, if the capillary tube apparatus is kept
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value of 'h' increases, if the capillary tube apparatus is kept
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The correct answer is:
in a lift going downward with acceleration (a) where a $ < \mathrm{g}$ (acceleration
due to gravity)
due to gravity)
$h=\frac{2 T \cos \theta}{r \rho g} \quad \therefore h \propto \frac{1}{g}$
In a lift going downwards with acceleration $a$, the apparent value of $g$ decreases and hence $b$ increases.
In a lift going downwards with acceleration $a$, the apparent value of $g$ decreases and hence $b$ increases.
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