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Wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
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$1215 Å$
Wavelength of light
$\begin{aligned}
& \frac{1}{\lambda}=R\left(\frac{1}{1^2}-\frac{1}{2^2}\right) \\
& \Rightarrow \quad \frac{1}{\lambda}=1.097 \times 10^7 \times \frac{3}{4} \\
& \therefore \quad \lambda=1.215 \times 10^{-7} \mathrm{~m}=1215 Å
\end{aligned}$
$\begin{aligned}
& \frac{1}{\lambda}=R\left(\frac{1}{1^2}-\frac{1}{2^2}\right) \\
& \Rightarrow \quad \frac{1}{\lambda}=1.097 \times 10^7 \times \frac{3}{4} \\
& \therefore \quad \lambda=1.215 \times 10^{-7} \mathrm{~m}=1215 Å
\end{aligned}$
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