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Question: Answered & Verified by Expert
Wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
PhysicsAtomic PhysicsJIPMERJIPMER 2010
Options:
  • A $6563 Å$
  • B $4102 Å$
  • C $4861 Å$
  • D $1215 Å$
Solution:
1164 Upvotes Verified Answer
The correct answer is: $1215 Å$
Wavelength of light
$\begin{aligned}
& \frac{1}{\lambda}=R\left(\frac{1}{1^2}-\frac{1}{2^2}\right) \\
& \Rightarrow \quad \frac{1}{\lambda}=1.097 \times 10^7 \times \frac{3}{4} \\
& \therefore \quad \lambda=1.215 \times 10^{-7} \mathrm{~m}=1215 Å
\end{aligned}$

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