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Wavelength of light used in an optical instrument are $\lambda_1=4000 Å$ and $\lambda_2=5000 Å$, then ratio of their respective resolving powers (corresponding to $\lambda_1$ and $\lambda_2$ ) is
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5 : 4
5 : 4
Resolving power $\alpha(1 / \lambda)$. Hence, $\frac{(\text { R.P })_1}{(\text { R.P })_2}=\frac{\lambda_2}{\lambda_1}=\frac{5}{4}$
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