We have a galvanometer of resistance 25 Ω . It is shunted by a 2 . 5 Ω wire. The part of the total current i 0 that flows through the galvanometer is given as

Question

We have a galvanometer of resistance 25 Ω . It is shunted by a 2 . 5 Ω wire. The part of the total current i 0 that flows through the galvanometer is given as, i i 0 = 1 11, i i 0 = 1 10, i i 0 = 1 9, i i 0 = 2 11

MARKS App · Accepted Answer

S = i g G i - i g ⇒ i g = i S G + S i ⁡ g ⁡ = i ⁡ S ⁡ G ⁡ + S ⁡ = i ⁡ 0 × 2.5 2 5 + 2.5 = i ⁡ 0 11

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