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What are the number of octahedral and tetrahedral voids in 0.3 mole substance respectively if it forms hcp structure?
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Verified Answer
The correct answer is:
$1.8066 \times 10^{23}$ and $3.6132 \times 10^{23}$
Number of atoms in $0.3 \mathrm{~mol}$
$$
\begin{aligned}
& =0.3 \times \mathrm{N}_{\mathrm{A}} \\
& =0.3 \times 6.022 \times 10^{23} \\
& =1.8066 \times 10^{23}
\end{aligned}
$$
i. For hep structure, Number of octahedral voids
$=$ Number of atoms
$$
=1.8066 \times 10^{23}
$$
ii. For hcp structure, Number of tetrahedral voids
$$
\begin{aligned}
& =2 \times \text { Number of atoms } \\
& =2 \times 1.8066 \times 10^{23} \\
& =3.6132 \times 10^{23}
\end{aligned}
$$
$$
\begin{aligned}
& =0.3 \times \mathrm{N}_{\mathrm{A}} \\
& =0.3 \times 6.022 \times 10^{23} \\
& =1.8066 \times 10^{23}
\end{aligned}
$$
i. For hep structure, Number of octahedral voids
$=$ Number of atoms
$$
=1.8066 \times 10^{23}
$$
ii. For hcp structure, Number of tetrahedral voids
$$
\begin{aligned}
& =2 \times \text { Number of atoms } \\
& =2 \times 1.8066 \times 10^{23} \\
& =3.6132 \times 10^{23}
\end{aligned}
$$
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