Search any question & find its solution
Question:
Answered & Verified by Expert
What are the order and degree respectively of the differential
equation
$\left.\left(d^{4} y / d x^{4}\right)^{3}\right\}^{2 / 3}-7 x\left(d^{3} y / d x^{3}\right)^{2}=8 ? \quad$
Options:
equation
$\left.\left(d^{4} y / d x^{4}\right)^{3}\right\}^{2 / 3}-7 x\left(d^{3} y / d x^{3}\right)^{2}=8 ? \quad$
Solution:
1414 Upvotes
Verified Answer
The correct answer is:
4,2
$\left\{\left(\frac{d^{4} y}{d x^{4}}\right)^{3}\right\}^{\frac{2}{3}}-7 x\left(\frac{d^{3} y}{d x^{3}}\right)^{2}=8$
$\Rightarrow\left(\frac{d^{4} y}{d x^{4}}\right)^{2}-7 x\left(\frac{d^{3} y}{d x^{3}}\right)^{2}=8$
- The order and degree of the given differential equation are 4 and 2 respectively.
$\Rightarrow\left(\frac{d^{4} y}{d x^{4}}\right)^{2}-7 x\left(\frac{d^{3} y}{d x^{3}}\right)^{2}=8$
- The order and degree of the given differential equation are 4 and 2 respectively.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.