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What is the amount of water formed by combustion of $1.6 \mathrm{~g}$ methane?
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$3.6 \mathrm{~g}$
$\mathrm{CH}_4+2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}$
$\frac{1.6}{16}=0.1 \mathrm{~mol}$
Moles of $\mathrm{H}_2 \mathrm{O}$ formed $=0.2 \mathrm{~mol}$
Mass of $\mathrm{H}_2 \mathrm{O}$ formed $=0.2 \times 18=3.6 \mathrm{~g}$
$\frac{1.6}{16}=0.1 \mathrm{~mol}$
Moles of $\mathrm{H}_2 \mathrm{O}$ formed $=0.2 \mathrm{~mol}$
Mass of $\mathrm{H}_2 \mathrm{O}$ formed $=0.2 \times 18=3.6 \mathrm{~g}$
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