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What is the binary equivalent of decimal number $(0.8125)_{10}$ ?
Options:
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Verified Answer
The correct answer is:
$(0.1101)_{2}$
Work with option $(0.1101)_{2}=1 \times 2^{-1}+1 \times 2^{-2}+1 \times 2^{-4}$
$=\frac{1}{2}+\frac{1}{4}+\frac{1}{16}=\frac{13}{16}=(0.8125)_{10}$
Hence option (a) gives the binary equivalent of given decimal number.
$=\frac{1}{2}+\frac{1}{4}+\frac{1}{16}=\frac{13}{16}=(0.8125)_{10}$
Hence option (a) gives the binary equivalent of given decimal number.
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